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TypeError: ‘stepUp’ called on an object that does not implement interface HTMLInputElement in jquery

  • austgl 发布于 4年前 (2015-01-20)
  • 分类：JavaScript
  • 阅读(11832)
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  1. $.post(requestUrl, {“action”:“register”,“user_name”:user_name,“active”: “1”,   
  2.         “user_password”: user_password, “role”: “8”, “mobile”: phone, “email”: email, “yanzheng”:yanzheng,“isCreate”:true},  

FIX:
You are sending the object element user_password. You should post the value of object in post method user_password.value($(“#user_password”).val()).
只因为写错了一个变量，擦擦，，

passwd = $(“#user_password”).val();
r_passwd = $(“#r_password”).val();

  1. $.post(requestUrl, {“action”:“register”,“user_name”:user_name,“active”: “1”,   
  2.         “user_password”: password, “role”: “8”, “mobile”: phone, “email”: email, “yanzheng”:yanzheng,“isCreate”:true},  

未经允许不得转载：ganlei的个人博客 » TypeError: ‘stepUp’ called on an object that does not implement interface HTMLInputElement in jquery

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